Integrand size = 21, antiderivative size = 77 \[ \int \frac {\csc (c+d x)}{\sqrt [3]{a+a \sin (c+d x)}} \, dx=-\frac {\sqrt [6]{2} \operatorname {AppellF1}\left (\frac {1}{2},1,\frac {5}{6},\frac {3}{2},1-\sin (c+d x),\frac {1}{2} (1-\sin (c+d x))\right ) \cos (c+d x)}{d \sqrt [6]{1+\sin (c+d x)} \sqrt [3]{a+a \sin (c+d x)}} \]
-2^(1/6)*AppellF1(1/2,1,5/6,3/2,1-sin(d*x+c),1/2-1/2*sin(d*x+c))*cos(d*x+c )/d/(1+sin(d*x+c))^(1/6)/(a+a*sin(d*x+c))^(1/3)
\[ \int \frac {\csc (c+d x)}{\sqrt [3]{a+a \sin (c+d x)}} \, dx=\int \frac {\csc (c+d x)}{\sqrt [3]{a+a \sin (c+d x)}} \, dx \]
Time = 0.35 (sec) , antiderivative size = 77, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {3042, 3266, 3042, 3264, 148, 333}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\csc (c+d x)}{\sqrt [3]{a \sin (c+d x)+a}} \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int \frac {1}{\sin (c+d x) \sqrt [3]{a \sin (c+d x)+a}}dx\) |
\(\Big \downarrow \) 3266 |
\(\displaystyle \frac {\sqrt [3]{\sin (c+d x)+1} \int \frac {\csc (c+d x)}{\sqrt [3]{\sin (c+d x)+1}}dx}{\sqrt [3]{a \sin (c+d x)+a}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {\sqrt [3]{\sin (c+d x)+1} \int \frac {1}{\sin (c+d x) \sqrt [3]{\sin (c+d x)+1}}dx}{\sqrt [3]{a \sin (c+d x)+a}}\) |
\(\Big \downarrow \) 3264 |
\(\displaystyle -\frac {\cos (c+d x) \int \frac {\csc (c+d x)}{\sqrt {1-\sin (c+d x)} (\sin (c+d x)+1)^{5/6}}d(1-\sin (c+d x))}{d \sqrt {1-\sin (c+d x)} \sqrt [6]{\sin (c+d x)+1} \sqrt [3]{a \sin (c+d x)+a}}\) |
\(\Big \downarrow \) 148 |
\(\displaystyle -\frac {2 \cos (c+d x) \int \frac {\csc (c+d x)}{(\sin (c+d x)+1)^{5/6}}d\sqrt {1-\sin (c+d x)}}{d \sqrt {1-\sin (c+d x)} \sqrt [6]{\sin (c+d x)+1} \sqrt [3]{a \sin (c+d x)+a}}\) |
\(\Big \downarrow \) 333 |
\(\displaystyle -\frac {\sqrt [6]{2} \cos (c+d x) \operatorname {AppellF1}\left (\frac {1}{2},1,\frac {5}{6},\frac {3}{2},1-\sin (c+d x),\frac {1}{2} (1-\sin (c+d x))\right )}{d \sqrt [6]{\sin (c+d x)+1} \sqrt [3]{a \sin (c+d x)+a}}\) |
-((2^(1/6)*AppellF1[1/2, 1, 5/6, 3/2, 1 - Sin[c + d*x], (1 - Sin[c + d*x]) /2]*Cos[c + d*x])/(d*(1 + Sin[c + d*x])^(1/6)*(a + a*Sin[c + d*x])^(1/3)))
3.2.8.3.1 Defintions of rubi rules used
Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_.)*((e_) + (f_.)*(x_))^(p_.), x_] :> With[{k = Denominator[m]}, Simp[k/b Subst[Int[x^(k*(m + 1) - 1)*(c + d*(x^k/b))^n*(e + f*(x^k/b))^p, x], x, (b*x)^(1/k)], x]] /; FreeQ[{b, c, d, e, f, n, p}, x] && FractionQ[m] && IntegerQ[p]
Int[((a_) + (b_.)*(x_)^2)^(p_)*((c_) + (d_.)*(x_)^2)^(q_), x_Symbol] :> Sim p[a^p*c^q*x*AppellF1[1/2, -p, -q, 3/2, (-b)*(x^2/a), (-d)*(x^2/c)], x] /; F reeQ[{a, b, c, d, p, q}, x] && NeQ[b*c - a*d, 0] && (IntegerQ[p] || GtQ[a, 0]) && (IntegerQ[q] || GtQ[c, 0])
Int[((d_.)*sin[(e_.) + (f_.)*(x_)])^(n_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)])^(m_), x_Symbol] :> Simp[(-b)*(d/b)^n*(Cos[e + f*x]/(f*Sqrt[a + b*Sin[e + f*x]]*Sqrt[a - b*Sin[e + f*x]])) Subst[Int[(a - x)^n*((2*a - x)^(m - 1 /2)/Sqrt[x]), x], x, a - b*Sin[e + f*x]], x] /; FreeQ[{a, b, d, e, f, m, n} , x] && EqQ[a^2 - b^2, 0] && !IntegerQ[m] && GtQ[a, 0] && GtQ[d/b, 0]
Int[((d_.)*sin[(e_.) + (f_.)*(x_)])^(n_.)*((a_) + (b_.)*sin[(e_.) + (f_.)*( x_)])^(m_), x_Symbol] :> Simp[a^IntPart[m]*((a + b*Sin[e + f*x])^FracPart[m ]/(1 + (b/a)*Sin[e + f*x])^FracPart[m]) Int[(1 + (b/a)*Sin[e + f*x])^m*(d *Sin[e + f*x])^n, x], x] /; FreeQ[{a, b, d, e, f, m, n}, x] && EqQ[a^2 - b^ 2, 0] && !IntegerQ[m] && !GtQ[a, 0]
\[\int \frac {\csc \left (d x +c \right )}{\left (a +a \sin \left (d x +c \right )\right )^{\frac {1}{3}}}d x\]
Timed out. \[ \int \frac {\csc (c+d x)}{\sqrt [3]{a+a \sin (c+d x)}} \, dx=\text {Timed out} \]
\[ \int \frac {\csc (c+d x)}{\sqrt [3]{a+a \sin (c+d x)}} \, dx=\int \frac {\csc {\left (c + d x \right )}}{\sqrt [3]{a \left (\sin {\left (c + d x \right )} + 1\right )}}\, dx \]
\[ \int \frac {\csc (c+d x)}{\sqrt [3]{a+a \sin (c+d x)}} \, dx=\int { \frac {\csc \left (d x + c\right )}{{\left (a \sin \left (d x + c\right ) + a\right )}^{\frac {1}{3}}} \,d x } \]
\[ \int \frac {\csc (c+d x)}{\sqrt [3]{a+a \sin (c+d x)}} \, dx=\int { \frac {\csc \left (d x + c\right )}{{\left (a \sin \left (d x + c\right ) + a\right )}^{\frac {1}{3}}} \,d x } \]
Timed out. \[ \int \frac {\csc (c+d x)}{\sqrt [3]{a+a \sin (c+d x)}} \, dx=\int \frac {1}{\sin \left (c+d\,x\right )\,{\left (a+a\,\sin \left (c+d\,x\right )\right )}^{1/3}} \,d x \]